C#: Return each DateTime between @from and @to, stepped by a TimeSpan

        /// <summary>

        ///     Return each <see cref="DateTime" /> between <paramref name="from" /> and <paramref name="to" />, stepped by a

        ///     <see cref="TimeSpan" /> (<paramref name="step" />).

        /// </summary>

        /// <param name="from"></param>

        /// <param name="to"></param>

        /// <param name="step"></param>

        /// <returns></returns>

        /// <remarks>//TODO Untested code!</remarks>

        /// <example>

        ///     var now = DateTime.UtcNow;

        ///     var then = now.AddMinutes( 10 );

        ///     var minutes = now.To( then, TimeSpan.FromMinutes( 1 ) );

        ///     foreach ( var dateTime in minutes ) { Console.WriteLine( dateTime ); }

        /// </example>

        public static IEnumerable<DateTime> To( this DateTime from, DateTime to, TimeSpan? step = null ) {

            if ( !step.HasValue ) {

                try {

                    var diff = @from <= to ? to.Subtract( @from ) : @from.Subtract( @from );

                    if ( diff.TotalDays > 0 ) {

                        step = TimeSpan.FromDays( 1 );

                    }

                    else if ( diff.TotalHours > 0 ) {

                        step = TimeSpan.FromHours( 1 );

                    }

                    else if ( diff.TotalMinutes > 0 ) {

                        step = TimeSpan.FromMinutes( 1 );

                    }

                    else if ( diff.TotalSeconds > 0 ) {

                        step = TimeSpan.FromSeconds( 1 );

                    }

                    else {

                        step = TimeSpan.FromMilliseconds( 1 );

                    }

                }

                catch ( ArgumentOutOfRangeException ) {

                    step = TimeSpan.MaxValue;

                }

            }

            if ( from <= to ) {

                for ( var dt = from; dt <= to; dt += step.Value ) {

                    yield return dt;

                }

            }

            else {

                for ( var dt = from; dt >= to; dt -= step.Value ) {

                    yield return dt;

                }

            }

        }